A Galvanic (Voltaic) Cell

Cu2+ + 2 e+ Cu(s) Eo = +0.34 volts Zn2+ + 2 e+ Zn(s) Eo = -0.76 volts Cu2+ + Zn(s) ---> Cu(s) + Zn2+ Oxidation takes place at the Zn (-) electrode. Reduction takes place at the Cu (+) electrode. The salt bridge allows ions to flow between the two sides keeping net charges neutral.